 Search

# Chapter 6

### 1. In a vessel of 8800 tonnes displacement and KG 6.2m, 200 tonnes of cargo was loaded in the lower hold 1.7m above the keel. Find the final KG.

Solution:

Given:-

Weight = 8800t, Original KG =6.2m, Cargo loaded = 200t, KG = 1.7m Final W – 9000 t Final VM 54900 tm

Final KG = (Final VM/ Final W) Final KG = (54900 / 9000) = 6.1m

Here ‘VM’ stands for vertical moments.

### 2. 600 tonnes of cargo were discharged from a vessel from the upper 11m above the keel. In the original KG displacement were 6m and 12600 tonnes, calculate the KG.

Solution:-

Given:- Weight =12600 t Original KG =6m Cargo discharged = 600 t,

Cargo discharge 11 m above the keel Final Weight =12000 t Final VM =69000tm

Final KG = (Final VM / Final Weight)

Final KG = ( 69,000 / 12000)

= 5.75m

### Solution: Final W 10000t Final VM =41000tm

Final KG = (Final VM / Final Weight) Final KG = ( 41000 / 10000 ) = 4.11m.

### 4. 500 tonnes of cargo of discharge from the lower the lower hold (KG 3m ) of a vessel whose displacement and KG before discharging were 11500 tonnes and 6.3m . Find the final KG.

Solution:

Given:-

Weight = 11500t Initial KG = 6.3m Cargo discharged = 500t, KG =3m Final W =11000t Final VM =70950tm

Final KG = (Final VM / Final Weight) Final KG = (70,950/11000) =6.45m

Solution:

Given:-